Hey there! Ready to crunch some numbers? Let’s dive into the world of statistics! Feel Free to reach out any time Contact Us

Maximum Likelihood Estimator for Negative Binomial

Maximum Likelihood Estimator in Negative Binomial Distribution, Likelihood function, likelihood equation

If we consider a sequence of independent $Bernoulli  \,  Trials$ each trials has two outcomes called "success" or "failure". In each trial the probability of success is $p$ and failure is $1-p$. We observe that until a predefined number $r$ succesess occur then the random number of observed failure, $X$ follows the $Negative\, Binomial\,Distribution (Pascal)$ distribution.

`X \sim NBD(r, p)`

Probability Mass Function of $NBD$

The probability mass function of negative binomial is:

Let $X_{1},X_{2},X_{3},............,X_{n}$ identically independent observations $\sim NBD(r,p)$.

`P(X \,=\,x) =p(x)= \begin{cases} \binom{x+r-1}{x}p^{r}(1-p)^{x}  &; x \in  0,1,2,..... \\ 0 &; otherwise \\ \end{cases}`

`P(X \,=\,x)=\binom{x+r-1}{x}p^{r}(1-p)^{x} ; x \in  0,1,2,..... \tag{1}`

<\div>

  • where $x$ are failures preceding the $rth$ success in $x+r$ trials.
  • $p$ is the probability of success remain constant in each trial.
  • $r$ is the no of success.

Maximum Likelihood Estimator

The likelihood function of random samples from NBD population is

`L = \prod_{i=1}^{n} p_{x_{i}}(x_{i} | r \, , p) \tag{2}`

`L = \prod_{i=1}^{n} \left[  \binom{x_{i}+r-1}{x_{i}}p^{r}(1-p)^{x_{i}} \right]`

`L = \prod_{i=1}^{n} \binom{x_{i}+r-1}{x_{i}} \prod_{i=1}^{n}(1-p)^{x_{i}} \prod_{i=1}^{n} p^{r}`

`L =  \prod_{i=1}^{n} \binom{x_{i}+r-1}{x_{i}} \times (1-p)^{\sum x_{i}} \times p^{rn}`

Now taking log both sides to make calculation easy

`\log (r \, , p | \underline{x}) = \sum_{i=1}^{n} \log \binom{x_{i}+r-1}{x_{i}} + \\ \sum_{i=1}^{n}x_{i} \log (1-p) + rn \log p \tag{3}`

<\div>

Now differrentiate $(3)$ partially with respect to parameter $p$.

`\frac{\partial}{\partial p}\left(\log (r \, , p | \underline{x})\right) = \sum_{i=1}^{n} x_{i}  \frac{1}{(1-p)}\times (-1) + \frac{rn}{p} \tag{4}`

Putting $(4)$ equal to zero and finding the value of $p$

`\frac{\partial}{\partial p}\left(\log (r \, , p | \underline{x})\right) = 0 \Rightarrow \frac{\sum x_i}{(1-p)} = \frac{rn}{p}`

`\frac{\sum x_i}{n(1-p)} = \frac{r}{p} \Rightarrow \frac{\overline{x}}{r} = \frac{(1-p)}{p}`

`\frac{\overline{x}}{r} = \frac{1}{p} - 1 \Rightarrow \frac{\overline{x}}{r} +1 = \frac{1}{p} \tag{5}`

finaly resolving the equation $(5)$ for $p$ we get mle for this as

`\hat{p}_{MLE} = \left( \frac{r}{\overline{x}_{n} + r}\right)`

R Code for NBD Plot

Negative Binomial Distribution Simulation

Post a Comment

Oops!
It seems there is something wrong with your internet connection. Please connect to the internet and start browsing again.
Site is Blocked
Sorry! This site is not available in your country.